Solving Linear Equations
Learn how to solve one-step and two-step linear equations using inverse operations.
Learning Objectives
What Are Equations?
An equation is a mathematical statement that shows two expressions are equal, connected by an equals sign (=). Think of an equation as a perfectly balanced scale: whatever is on the left side must equal what’s on the right side.
For example, in the equation x + 5 = 12, we’re saying “some number plus 5 equals 12.” The unknown number is represented by a variable, usually a letter like x, y, or n.
Key Vocabulary
- Variable: A letter or symbol representing an unknown number (like x, y, or n)
- Coefficient: The number multiplied by a variable (in 3x, the coefficient is 3)
- Constant: A number on its own (like 5, -2, or 100)
- Solution: The value of the variable that makes the equation true
- Inverse Operations: Opposite operations that undo each other
The Golden Rule: Keep It Balanced
The most important principle in solving equations is balance. Whatever you do to one side of the equation, you must do to the other side. This keeps the equation equal, just like keeping a scale balanced.
Think of it this way: If you have a balanced scale and you add 3 kg to the left side, you must add 3 kg to the right side to keep it balanced. The same applies to equations.
Inverse Operations: The Key to Solving
Inverse operations are mathematical opposites that undo each other. We use them to isolate the variable (get it by itself on one side of the equation).
The main inverse operation pairs are:
- Addition ↔ Subtraction: Adding 5 is undone by subtracting 5
- Multiplication ↔ Division: Multiplying by 3 is undone by dividing by 3
One-Step Equations
One-step equations require only one inverse operation to solve.
Type 1: Addition Equations
When a number is added to the variable, subtract that number from both sides.
Pattern: x + a = b, so x = b - a
Example 1: Basic Addition
Solve: x + 7 = 15
Solution:
x + 7 = 15
x + 7 - 7 = 15 - 7 (Subtract 7 from both sides)
x = 8Check: 8 + 7 = 15 ✓
Type 2: Subtraction Equations
When a number is subtracted from the variable, add that number to both sides.
Pattern: x - a = b, so x = b + a
Example 2: Basic Subtraction
Solve: x - 9 = 14
Solution:
x - 9 = 14
x - 9 + 9 = 14 + 9 (Add 9 to both sides)
x = 23Check: 23 - 9 = 14 ✓
Type 3: Multiplication Equations
When a variable is multiplied by a number, divide both sides by that number.
Pattern: ax = b, so x = b ÷ a
Example 3: Basic Multiplication
Solve: 5x = 35
Solution:
5x = 35
5x ÷ 5 = 35 ÷ 5 (Divide both sides by 5)
x = 7Check: 5 × 7 = 35 ✓
Type 4: Division Equations
When a variable is divided by a number, multiply both sides by that number.
Pattern: x ÷ a = b, so x = b × a
Example 4: Basic Division
Solve: x ÷ 4 = 9
Solution:
x ÷ 4 = 9
x ÷ 4 × 4 = 9 × 4 (Multiply both sides by 4)
x = 36Check: 36 ÷ 4 = 9 ✓
Two-Step Equations
Two-step equations require two inverse operations to solve. The key is to work in reverse order of operations:
- First, undo addition or subtraction
- Then, undo multiplication or division
The Standard Form: ax + b = c
Most two-step equations follow this pattern, where you need to:
- Subtract b from both sides (or add if it’s negative)
- Divide both sides by a (or multiply if it’s a fraction)
Example 5: Standard Two-Step
Solve: 3x + 8 = 23
Solution:
3x + 8 = 23
3x + 8 - 8 = 23 - 8 (Step 1: Subtract 8 from both sides)
3x = 15
3x ÷ 3 = 15 ÷ 3 (Step 2: Divide both sides by 3)
x = 5Check: 3(5) + 8 = 15 + 8 = 23 ✓
Example 6: Two-Step with Subtraction
Solve: 2x - 6 = 10
Solution:
2x - 6 = 10
2x - 6 + 6 = 10 + 6 (Step 1: Add 6 to both sides)
2x = 16
2x ÷ 2 = 16 ÷ 2 (Step 2: Divide both sides by 2)
x = 8Check: 2(8) - 6 = 16 - 6 = 10 ✓
Example 7: Two-Step with Larger Numbers
Solve: 7x + 15 = 50
Solution:
7x + 15 = 50
7x + 15 - 15 = 50 - 15 (Subtract 15 from both sides)
7x = 35
7x ÷ 7 = 35 ÷ 7 (Divide both sides by 7)
x = 5Check: 7(5) + 15 = 35 + 15 = 50 ✓
Example 8: Two-Step with Negative Coefficient
Solve: -4x + 12 = 0
Solution:
-4x + 12 = 0
-4x + 12 - 12 = 0 - 12 (Subtract 12 from both sides)
-4x = -12
-4x ÷ (-4) = -12 ÷ (-4) (Divide both sides by -4)
x = 3Check: -4(3) + 12 = -12 + 12 = 0 ✓
Equations with Variables on Both Sides
Sometimes variables appear on both sides of the equation. The strategy is to collect all variable terms on one side and all constant terms on the other.
Example 9: Variables on Both Sides
Solve: 5x + 3 = 2x + 15
Solution:
5x + 3 = 2x + 15
5x - 2x + 3 = 2x - 2x + 15 (Subtract 2x from both sides)
3x + 3 = 15
3x + 3 - 3 = 15 - 3 (Subtract 3 from both sides)
3x = 12
3x ÷ 3 = 12 ÷ 3 (Divide both sides by 3)
x = 4Check: 5(4) + 3 = 20 + 3 = 23, and 2(4) + 15 = 8 + 15 = 23 ✓
Step-by-Step Strategy for Solving Equations
Follow these steps for any linear equation:
- Simplify both sides if needed (combine like terms)
- Move variable terms to one side using inverse operations
- Move constant terms to the other side using inverse operations
- Isolate the variable by dividing or multiplying
- Check your solution by substituting back into the original equation
Common Errors and How to Avoid Them
| Error | Example | Correction | Why It Matters |
|---|---|---|---|
| Only changing one side | x + 5 = 12, so x = 12 - 5 but wrote x + 5 = 7 | Apply operation to BOTH sides: x + 5 - 5 = 12 - 5 | Maintains equality |
| Wrong inverse operation | x + 5 = 12, so x + 5 + 5 = 12 + 5 | Use subtraction (inverse of addition) | Must undo the operation |
| Incorrect sign when subtracting | 2x - 6 = 10, then 2x = 10 - 6 = 4 | When moving -6, add 6: 2x = 10 + 6 = 16 | Sign changes when moving across = |
| Dividing only one term | 3x + 6 = 18, then x + 6 = 6 | Divide ALL terms: (3x + 6) ÷ 3 or isolate first | Division applies to whole side |
| Arithmetic mistakes | 15 ÷ 3 = 4 | Double-check: 15 ÷ 3 = 5 | One error ruins entire solution |
| Not checking the answer | Solved x = 5 but didn’t verify | Substitute x = 5 into original equation | Catches calculation errors |
Practice Problems
One-Step Equations
Solve: x + 15 = 28 Answer: x = 13
Solve: x - 9 = 17 Answer: x = 26
Solve: 6x = 42 Answer: x = 7
Solve: x ÷ 5 = 8 Answer: x = 40
Solve: x + 23 = 50 Answer: x = 27
Solve: 9x = 72 Answer: x = 8
Two-Step Equations
Solve: 2x + 5 = 19 Answer: x = 7
Solve: 3x - 7 = 14 Answer: x = 7
Solve: 5x + 12 = 37 Answer: x = 5
Solve: 4x - 9 = 27 Answer: x = 9
Solve: 6x + 8 = 44 Answer: x = 6
Solve: 7x - 15 = 20 Answer: x = 5
Challenge Problems
Solve: 8x + 25 = 73 Answer: x = 6
Solve: -3x + 18 = 6 Answer: x = 4
Solve: 5x + 3 = 3x + 19 Answer: x = 8
Solve: 12 - 2x = 4 Answer: x = 4
Solve: 10x - 35 = 65 Answer: x = 10
Solve: 4x + 7 = 2x + 23 Answer: x = 8
Real-World Applications
Application 1: Shopping Budget
Problem: You have 12, and you want to buy a bookmark for $13. How many books can you buy?
Solution: Let x = number of books Equation: 12x + 13 = 85
12x + 13 = 85
12x = 72
x = 6You can buy 6 books.
Application 2: Temperature Conversion
Problem: The formula to convert Celsius to Fahrenheit is F = (9/5)C + 32. If the temperature is 77°F, what is it in Celsius?
Solution:
77 = (9/5)C + 32
77 - 32 = (9/5)C
45 = (9/5)C
45 × (5/9) = C
25 = CThe temperature is 25°C.
Application 3: Savings Plan
Problem: Emily wants to save 120 saved and plans to save $15 per week. How many weeks until she reaches her goal?
Solution: Let x = number of weeks Equation: 120 + 15x = 450
120 + 15x = 450
15x = 330
x = 22Emily needs to save for 22 weeks.
Application 4: Age Problems
Problem: Sarah is 4 years older than twice her brother’s age. If Sarah is 18, how old is her brother?
Solution: Let x = brother’s age Equation: 2x + 4 = 18
2x + 4 = 18
2x = 14
x = 7Sarah’s brother is 7 years old.
Application 5: Perimeter Problems
Problem: A rectangle has a perimeter of 46 cm. Its length is 13 cm. What is its width?
Solution: Perimeter formula: P = 2l + 2w Let w = width
46 = 2(13) + 2w
46 = 26 + 2w
20 = 2w
w = 10The width is 10 cm.
Why This Matters
Understanding how to solve equations is fundamental to algebra and mathematics beyond middle school. Equations allow us to:
- Model real situations with mathematical language
- Find unknown quantities in science, engineering, and everyday life
- Make predictions and solve problems systematically
- Think logically about relationships between quantities
- Build a foundation for advanced mathematics in high school and beyond
From calculating discounts while shopping to predicting future savings, from converting recipes to solving physics problems, equation-solving skills are tools you’ll use throughout your life. Every time you think “I need to figure out what number makes this work,” you’re thinking algebraically.
Connection to Other Topics
Solving equations connects to many other mathematical concepts:
- Order of Operations: Understanding PEMDAS helps you simplify equations correctly
- Properties of Equality: Addition, subtraction, multiplication, and division properties justify each step
- Integer Operations: Working with positive and negative numbers in equations
- Fractions and Decimals: Equations can involve any type of number
- Graphing: Solutions to equations can be visualized on coordinate planes
- Functions: Equations are the foundation for understanding functions in high school
Tips for Success
- Always write your work neatly: Show each step clearly so you can check your work
- Check your answer: Substitute your solution back into the original equation
- Keep the equation balanced: Whatever you do to one side, do to the other
- Work in reverse order: Undo addition/subtraction first, then multiplication/division
- Practice regularly: The more equations you solve, the more confident you’ll become
- Learn from mistakes: If you get an answer wrong, figure out where you went wrong
- Use estimation: Before solving, estimate what the answer might be
- Stay organized: Line up equals signs vertically to see the steps clearly
Mastering equation solving takes practice, but with patience and persistence, you’ll develop a powerful mathematical skill that opens doors to advanced mathematics and real-world problem solving.
Worked Examples
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